Help with navigation planning.

[tragik]

I hope this is the right place to help me out with this... first off, i love to fly simulation WWII flying and navigation. Here is my problem and maybe someone can help me with flight conversion. (keep in mind, fuel and winds wont take effect as of right now).

Here is a plane example. : Douglas A-20G "Havoc" (1943)
Climb rate: 248Km/h at 16.71 meters/sec
Maximum Level speed at sea level: 430Km/h

if this plane flies 420Km/h for one hour, it will naturally travel 420 Km

Here I am stuck:
If this plane flies 248km/h rising 16.71 m/s (meters per second) for one hour it would be at 60,156 meters (naturally this is without consideration to changing supercharger and air density) above sea level. (right?). But due to rise and speed the two planes (one level, one climbing) will not meet in the same place at that one hour mark, the climbing airplane would be at a shorter distance (am i correct in this theory).
So with all this confusion my questions are...

how could i figure out the distance traveled when my plane flies 248km/h with a 16.71 m/s (meters per second) when i reach a certain altitude (say 1000 meters)?

How can i figure out the angle of rise for a 16.71 m/s (not sure if speed matters in this question) in degree, say 30 degree angle rise? (not sure if this is even important)

I know this is a 'real' pilots area and am ready to get laughed out of here, but i have googled it and dont even know how to call this conversion.. This had to of been done in the olden days some way.. a math equation, a conversion..

any suggestions would be greatly appreciated.. thanks.

[hiigaran]

as far as i know, you cant. not with that information anyway. for knowing what distance you traveled, you need your groundspeed, not your airspeed. you dont want to know your airspeed because were not looking for how fast the air hits your aircraft, but instead, how fast the aircraft flies in relation to the ground. so suppose we replaced your climb rate airspeed with your groundspeed, heres how youd figure it out:

draw a right angled triangle. label your three sides as altitude (the vertical line), ground (horizontal line) and track (hypotenuse). you want to find the angle of the climb, so therefore you would label the angle between ground and track as x (or whatever you want).

to find x (you need a calculator for this stuff), you would need to use tan-1(-1 is superscripted). so youd do tan-1(60156/248000). 248000 is 248 km converted into meters. hit equals, and then press your degrees conversion button. your answer comes down to 14 degrees rounded off to the nearest degree.


sounds complex, but isnt all that hard. just find your groundspeed first and you got it all set.